If I understood correctly, it doesn't matter whether the nonnegative matrix A is irreducible or not, it always has a Frobenius normal form. However, is irreducibility (or reducibility) of A somehow reflected in the normal form?
If I understood correctly, it doesn't matter whether the nonnegative matrix A is irreducible or not, it always has a Frobenius normal form. However, is irreducibility (or reducibility) of A somehow reflected in the normal form?
Fascinating post, many thanks!
If I understood correctly, it doesn't matter whether the nonnegative matrix A is irreducible or not, it always has a Frobenius normal form. However, is irreducibility (or reducibility) of A somehow reflected in the normal form?
Hi! Thanks :)
An irreducible matrix is already in Frobenius normal form: it only has a single block.